Search a number
-
+
232540121223433 is a prime number
BaseRepresentation
bin110100110111111001110111…
…010100100101000100001001
31010111100121200212112201001101
4310313321313110211010021
5220434414132013122213
62142323242410021401
766660316661120362
oct6467716724450411
91114317625481041
10232540121223433
1168104791138681
12220b7a00117861
139c9a5932c754a
14415d0053a8b69
151bd3d7ee08bdd
hexd37e77525109

232540121223433 has 2 divisors, whose sum is σ = 232540121223434. Its totient is φ = 232540121223432.

The previous prime is 232540121223427. The next prime is 232540121223467. The reversal of 232540121223433 is 334322121045232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 213167825671824 + 19372295551609 = 14600268^2 + 4401397^2 .

It is a cyclic number.

It is not a de Polignac number, because 232540121223433 - 233 = 232531531288841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 232540121223392 and 232540121223401.

It is not a weakly prime, because it can be changed into another prime (232540121223493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116270060611716 + 116270060611717.

It is an arithmetic number, because the mean of its divisors is an integer number (116270060611717).

Almost surely, 2232540121223433 is an apocalyptic number.

It is an amenable number.

232540121223433 is a deficient number, since it is larger than the sum of its proper divisors (1).

232540121223433 is an equidigital number, since it uses as much as digits as its factorization.

232540121223433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 37.

Adding to 232540121223433 its reverse (334322121045232), we get a palindrome (566862242268665).

The spelling of 232540121223433 in words is "two hundred thirty-two trillion, five hundred forty billion, one hundred twenty-one million, two hundred twenty-three thousand, four hundred thirty-three".