Base | Representation |
---|---|
bin | 1010100100110100100011… |
… | …10110110010101001110001 |
3 | 10001100012020210220001210022 |
4 | 11102122101312302221301 |
5 | 11022004024400000423 |
6 | 121243214442013225 |
7 | 4620101330325221 |
oct | 522322166625161 |
9 | 101305223801708 |
10 | 23255400000113 |
11 | 745661803aa76 |
12 | 27370764a7215 |
13 | cc8c89872a58 |
14 | 5a57d2bcc081 |
15 | 2a4dd650ddc8 |
hex | 152691db2a71 |
23255400000113 has 32 divisors (see below), whose sum is σ = 26057049034752. Its totient is φ = 20641886003200.
The previous prime is 23255400000089. The next prime is 23255400000127. The reversal of 23255400000113 is 31100000455232.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 23255400000113 - 216 = 23255399934577 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23255400000163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7061093 + ... + 9816813.
It is an arithmetic number, because the mean of its divisors is an integer number (814282782336).
Almost surely, 223255400000113 is an apocalyptic number.
23255400000113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
23255400000113 is a deficient number, since it is larger than the sum of its proper divisors (2801649034639).
23255400000113 is a wasteful number, since it uses less digits than its factorization.
23255400000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2756065.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 23255400000113 its reverse (31100000455232), we get a palindrome (54355400455345).
The spelling of 23255400000113 in words is "twenty-three trillion, two hundred fifty-five billion, four hundred million, one hundred thirteen", and thus it is an aban number.
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