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23276171555753 is a prime number
BaseRepresentation
bin1010100101011011001111…
…11011111111001110101001
310001102011212102020102101212
411102231213323333032221
511022324044404241003
6121300531532322505
74621435141536404
oct522554773771651
9101364772212355
1023276171555753
117464407042186
12273b0b2913435
13ccac1a05168c
145a6803756d3b
152a56eed83dd8
hex152b67eff3a9

23276171555753 has 2 divisors, whose sum is σ = 23276171555754. Its totient is φ = 23276171555752.

The previous prime is 23276171555743. The next prime is 23276171555773. The reversal of 23276171555753 is 35755517167232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23032819759504 + 243351796249 = 4799252^2 + 493307^2 .

It is a cyclic number.

It is not a de Polignac number, because 23276171555753 - 210 = 23276171554729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23276171555692 and 23276171555701.

It is not a weakly prime, because it can be changed into another prime (23276171555743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11638085777876 + 11638085777877.

It is an arithmetic number, because the mean of its divisors is an integer number (11638085777877).

Almost surely, 223276171555753 is an apocalyptic number.

It is an amenable number.

23276171555753 is a deficient number, since it is larger than the sum of its proper divisors (1).

23276171555753 is an equidigital number, since it uses as much as digits as its factorization.

23276171555753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46305000, while the sum is 59.

The spelling of 23276171555753 in words is "twenty-three trillion, two hundred seventy-six billion, one hundred seventy-one million, five hundred fifty-five thousand, seven hundred fifty-three".