Base | Representation |
---|---|
bin | 1010100110001010000101… |
… | …11010001010001110101111 |
3 | 10001111120210001201000120221 |
4 | 11103011002322022032233 |
5 | 11023232100422421221 |
6 | 121320251221352211 |
7 | 4623315302043346 |
oct | 523050272121657 |
9 | 101446701630527 |
10 | 23301320123311 |
11 | 747404182220a |
12 | 2743b50b68667 |
13 | 10003c72a4a99 |
14 | 5a7b0b734b5d |
15 | 2a61c2b01541 |
hex | 153142e8a3af |
23301320123311 has 4 divisors (see below), whose sum is σ = 23302271960224. Its totient is φ = 23300368286400.
The previous prime is 23301320123309. The next prime is 23301320123339. The reversal of 23301320123311 is 11332102310332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23301320123311 - 21 = 23301320123309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23301320127311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475881735 + ... + 475930696.
It is an arithmetic number, because the mean of its divisors is an integer number (5825567990056).
Almost surely, 223301320123311 is an apocalyptic number.
23301320123311 is a deficient number, since it is larger than the sum of its proper divisors (951836913).
23301320123311 is an equidigital number, since it uses as much as digits as its factorization.
23301320123311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 951836912.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 23301320123311 its reverse (11332102310332), we get a palindrome (34633422433643).
The spelling of 23301320123311 in words is "twenty-three trillion, three hundred one billion, three hundred twenty million, one hundred twenty-three thousand, three hundred eleven".
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