Base | Representation |
---|---|
bin | 1101100100001001001… |
… | …0101111011011110001 |
3 | 211021111222201002202000 |
4 | 3121002102233123301 |
5 | 12304231323134441 |
6 | 255020213244213 |
7 | 22556650040343 |
oct | 3310222573361 |
9 | 737458632660 |
10 | 233040443121 |
11 | 8a917289142 |
12 | 391b8933669 |
13 | 18c8b588c35 |
14 | b3ca25d293 |
15 | 60dde802b6 |
hex | 36424af6f1 |
233040443121 has 64 divisors (see below), whose sum is σ = 364179456000. Its totient is φ = 147064438080.
The previous prime is 233040443089. The next prime is 233040443261. The reversal of 233040443121 is 121344040332.
233040443121 is a `hidden beast` number, since 2 + 3 + 304 + 0 + 44 + 312 + 1 = 666.
It is not a de Polignac number, because 233040443121 - 25 = 233040443089 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (233040443821) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17686866 + ... + 17700036.
It is an arithmetic number, because the mean of its divisors is an integer number (5690304000).
Almost surely, 2233040443121 is an apocalyptic number.
It is an amenable number.
233040443121 is a deficient number, since it is larger than the sum of its proper divisors (131139012879).
233040443121 is a wasteful number, since it uses less digits than its factorization.
233040443121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13651 (or 13645 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 233040443121 its reverse (121344040332), we get a palindrome (354384483453).
The spelling of 233040443121 in words is "two hundred thirty-three billion, forty million, four hundred forty-three thousand, one hundred twenty-one".
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