Base | Representation |
---|---|
bin | 1101100100011100111… |
… | …0001010111100001011 |
3 | 211021201202022002101111 |
4 | 3121013032022330023 |
5 | 12304414010144042 |
6 | 255032325431151 |
7 | 22562002630324 |
oct | 3310716127413 |
9 | 737652262344 |
10 | 233123131147 |
11 | 8a959a25955 |
12 | 3922056b4b7 |
13 | 18ca274a96a |
14 | b3d722544b |
15 | 60e6365517 |
hex | 364738af0b |
233123131147 has 2 divisors, whose sum is σ = 233123131148. Its totient is φ = 233123131146.
The previous prime is 233123131081. The next prime is 233123131151. The reversal of 233123131147 is 741131321332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 233123131147 - 27 = 233123131019 is a prime.
It is not a weakly prime, because it can be changed into another prime (233123131247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116561565573 + 116561565574.
It is an arithmetic number, because the mean of its divisors is an integer number (116561565574).
Almost surely, 2233123131147 is an apocalyptic number.
233123131147 is a deficient number, since it is larger than the sum of its proper divisors (1).
233123131147 is an equidigital number, since it uses as much as digits as its factorization.
233123131147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9072, while the sum is 31.
Adding to 233123131147 its reverse (741131321332), we get a palindrome (974254452479).
The spelling of 233123131147 in words is "two hundred thirty-three billion, one hundred twenty-three million, one hundred thirty-one thousand, one hundred forty-seven".
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