Base | Representation |
---|---|
bin | 100001111011010011000… |
… | …111000100111000010001 |
3 | 22020212210020222121210020 |
4 | 201323103013010320101 |
5 | 301144214003401001 |
6 | 4543011543454053 |
7 | 330303421030056 |
oct | 41732307047021 |
9 | 8225706877706 |
10 | 2331414122001 |
11 | 819824545988 |
12 | 317a15a57329 |
13 | 13bb0b70c643 |
14 | 80babb8702d |
15 | 409a34e9736 |
hex | 21ed31c4e11 |
2331414122001 has 4 divisors (see below), whose sum is σ = 3108552162672. Its totient is φ = 1554276081332.
The previous prime is 2331414121973. The next prime is 2331414122017. The reversal of 2331414122001 is 1002214141332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2331414122001 - 26 = 2331414121937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2331414129001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388569020331 + ... + 388569020336.
It is an arithmetic number, because the mean of its divisors is an integer number (777138040668).
Almost surely, 22331414122001 is an apocalyptic number.
It is an amenable number.
2331414122001 is a deficient number, since it is larger than the sum of its proper divisors (777138040671).
2331414122001 is an equidigital number, since it uses as much as digits as its factorization.
2331414122001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 777138040670.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 2331414122001 its reverse (1002214141332), we get a palindrome (3333628263333).
The spelling of 2331414122001 in words is "two trillion, three hundred thirty-one billion, four hundred fourteen million, one hundred twenty-two thousand, one".
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