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2331414121973 is a prime number
BaseRepresentation
bin100001111011010011000…
…111000100110111110101
322020212210020222121202012
4201323103013010313311
5301144214003400343
64543011543454005
7330303421030016
oct41732307046765
98225706877665
102331414121973
11819824545962
12317a15a57305
1313bb0b70c621
1480babb8700d
15409a34e9718
hex21ed31c4df5

2331414121973 has 2 divisors, whose sum is σ = 2331414121974. Its totient is φ = 2331414121972.

The previous prime is 2331414121957. The next prime is 2331414122017. The reversal of 2331414121973 is 3791214141332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1667347222564 + 664066899409 = 1291258^2 + 814903^2 .

It is a cyclic number.

It is not a de Polignac number, because 2331414121973 - 24 = 2331414121957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2331414121973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2331414121943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165707060986 + 1165707060987.

It is an arithmetic number, because the mean of its divisors is an integer number (1165707060987).

Almost surely, 22331414121973 is an apocalyptic number.

It is an amenable number.

2331414121973 is a deficient number, since it is larger than the sum of its proper divisors (1).

2331414121973 is an equidigital number, since it uses as much as digits as its factorization.

2331414121973 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108864, while the sum is 41.

The spelling of 2331414121973 in words is "two trillion, three hundred thirty-one billion, four hundred fourteen million, one hundred twenty-one thousand, nine hundred seventy-three".