Base | Representation |
---|---|
bin | 110101000001100100011110… |
… | …000110100101110011111111 |
3 | 1010120201010011201110212000121 |
4 | 311001210132012211303333 |
5 | 221031304444121041020 |
6 | 2143552332524035411 |
7 | 100056313023210664 |
oct | 6501443606456377 |
9 | 1116633151425017 |
10 | 233204344315135 |
11 | 68340452817566 |
12 | 221a4693092b67 |
13 | a0180c95b435b |
14 | 4183216d29a6b |
15 | 1be62a811abaa |
hex | d4191e1a5cff |
233204344315135 has 32 divisors (see below), whose sum is σ = 290169444407040. Its totient is φ = 179710739109888.
The previous prime is 233204344315121. The next prime is 233204344315157. The reversal of 233204344315135 is 531513443402332.
It is not a de Polignac number, because 233204344315135 - 227 = 233204210097407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 233204344315091 and 233204344315100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 476399514 + ... + 476888776.
It is an arithmetic number, because the mean of its divisors is an integer number (9067795137720).
Almost surely, 2233204344315135 is an apocalyptic number.
233204344315135 is a deficient number, since it is larger than the sum of its proper divisors (56965100091905).
233204344315135 is a wasteful number, since it uses less digits than its factorization.
233204344315135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 496947.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 233204344315135 its reverse (531513443402332), we get a palindrome (764717787717467).
The spelling of 233204344315135 in words is "two hundred thirty-three trillion, two hundred four billion, three hundred forty-four million, three hundred fifteen thousand, one hundred thirty-five".
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