Base | Representation |
---|---|
bin | 100001111100000011111… |
… | …010110110010010110001 |
3 | 22020221220022211221101012 |
4 | 201330003322312102301 |
5 | 301202403122000423 |
6 | 4543225115120305 |
7 | 330332623260602 |
oct | 41740372662261 |
9 | 8227808757335 |
10 | 2332233000113 |
11 | 81a104800155 |
12 | 318004143095 |
13 | 13bc0c2720c3 |
14 | 80c48827da9 |
15 | 40a00350078 |
hex | 21f03eb64b1 |
2332233000113 has 2 divisors, whose sum is σ = 2332233000114. Its totient is φ = 2332233000112.
The previous prime is 2332233000047. The next prime is 2332233000217. The reversal of 2332233000113 is 3110003322332.
2332233000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2248869142129 + 83363857984 = 1499623^2 + 288728^2 .
It is a cyclic number.
It is not a de Polignac number, because 2332233000113 - 212 = 2332232996017 is a prime.
It is not a weakly prime, because it can be changed into another prime (2332223000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1166116500056 + 1166116500057.
It is an arithmetic number, because the mean of its divisors is an integer number (1166116500057).
Almost surely, 22332233000113 is an apocalyptic number.
It is an amenable number.
2332233000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2332233000113 is an equidigital number, since it uses as much as digits as its factorization.
2332233000113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 2332233000113 its reverse (3110003322332), we get a palindrome (5442236322445).
The spelling of 2332233000113 in words is "two trillion, three hundred thirty-two billion, two hundred thirty-three million, one hundred thirteen", and thus it is an aban number.
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