Base | Representation |
---|---|
bin | 100001111100001001010… |
… | …010100110100010111011 |
3 | 22020222010121102011012222 |
4 | 201330021102212202323 |
5 | 301203044204110042 |
6 | 4543242054354255 |
7 | 330335066234036 |
oct | 41741122464273 |
9 | 8228117364188 |
10 | 2332323113147 |
11 | 81a150659435 |
12 | 31802a35b98b |
13 | 13bc24b33621 |
14 | 80c567a401d |
15 | 40a082002d2 |
hex | 21f094a68bb |
2332323113147 has 2 divisors, whose sum is σ = 2332323113148. Its totient is φ = 2332323113146.
The previous prime is 2332323113011. The next prime is 2332323113161. The reversal of 2332323113147 is 7413113232332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2332323113147 - 216 = 2332323047611 is a prime.
It is a super-2 number, since 2×23323231131472 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2332320113147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1166161556573 + 1166161556574.
It is an arithmetic number, because the mean of its divisors is an integer number (1166161556574).
Almost surely, 22332323113147 is an apocalyptic number.
2332323113147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2332323113147 is an equidigital number, since it uses as much as digits as its factorization.
2332323113147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54432, while the sum is 35.
Adding to 2332323113147 its reverse (7413113232332), we get a palindrome (9745436345479).
The spelling of 2332323113147 in words is "two trillion, three hundred thirty-two billion, three hundred twenty-three million, one hundred thirteen thousand, one hundred forty-seven".
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