Base | Representation |
---|---|
bin | 100001111100110100111… |
… | …011000010101000100101 |
3 | 22021001000121211200101111 |
4 | 201330310323002220211 |
5 | 301211044103243440 |
6 | 4543442444225021 |
7 | 330362165302243 |
oct | 41746473025045 |
9 | 8231017750344 |
10 | 2333055134245 |
11 | 81a496889750 |
12 | 3181b353b171 |
13 | 13c0106a48c4 |
14 | 80cc5ab5793 |
15 | 40a4c5ea4ea |
hex | 21f34ec2a25 |
2333055134245 has 32 divisors (see below), whose sum is σ = 3074258157696. Its totient is φ = 1685617939200.
The previous prime is 2333055134239. The next prime is 2333055134251. The reversal of 2333055134245 is 5424315503332.
It is an interprime number because it is at equal distance from previous prime (2333055134239) and next prime (2333055134251).
It is not a de Polignac number, because 2333055134245 - 29 = 2333055133733 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2333055134198 and 2333055134207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47269230 + ... + 47318560.
It is an arithmetic number, because the mean of its divisors is an integer number (96070567428).
Almost surely, 22333055134245 is an apocalyptic number.
It is an amenable number.
2333055134245 is a deficient number, since it is larger than the sum of its proper divisors (741203023451).
2333055134245 is a wasteful number, since it uses less digits than its factorization.
2333055134245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54981.
The product of its (nonzero) digits is 648000, while the sum is 40.
The spelling of 2333055134245 in words is "two trillion, three hundred thirty-three billion, fifty-five million, one hundred thirty-four thousand, two hundred forty-five".
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