Base | Representation |
---|---|
bin | 1010100111010111111111… |
… | …10000001101000111110001 |
3 | 10001122120201210001001002111 |
4 | 11103223333300031013301 |
5 | 11024423224114110301 |
6 | 121351405241245321 |
7 | 4626325563432442 |
oct | 523537760150761 |
9 | 101576653031074 |
10 | 23343143113201 |
11 | 748a85380756a |
12 | 2750083493841 |
13 | 1004330c36692 |
14 | 5a9b580812c9 |
15 | 2a731e683551 |
hex | 153affc0d1f1 |
23343143113201 has 2 divisors, whose sum is σ = 23343143113202. Its totient is φ = 23343143113200.
The previous prime is 23343143113117. The next prime is 23343143113243. The reversal of 23343143113201 is 10231134134332.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23000273139600 + 342869973601 = 4795860^2 + 585551^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23343143113201 is a prime.
It is not a weakly prime, because it can be changed into another prime (23343143113261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11671571556600 + 11671571556601.
It is an arithmetic number, because the mean of its divisors is an integer number (11671571556601).
Almost surely, 223343143113201 is an apocalyptic number.
It is an amenable number.
23343143113201 is a deficient number, since it is larger than the sum of its proper divisors (1).
23343143113201 is an equidigital number, since it uses as much as digits as its factorization.
23343143113201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 23343143113201 its reverse (10231134134332), we get a palindrome (33574277247533).
The spelling of 23343143113201 in words is "twenty-three trillion, three hundred forty-three billion, one hundred forty-three million, one hundred thirteen thousand, two hundred one".
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