Base | Representation |
---|---|
bin | 100001111110001011101… |
… | …110110001000000000001 |
3 | 22021011210010022110101011 |
4 | 201332023232301000001 |
5 | 301222034423042311 |
6 | 4544243152040521 |
7 | 330443241426016 |
oct | 41761356610001 |
9 | 8234703273334 |
10 | 2334511534081 |
11 | 82007399a481 |
12 | 31853b233141 |
13 | 13c1b333c75c |
14 | 80dc32a970d |
15 | 40ad53d1321 |
hex | 21f8bbb1001 |
2334511534081 has 2 divisors, whose sum is σ = 2334511534082. Its totient is φ = 2334511534080.
The previous prime is 2334511534039. The next prime is 2334511534129. The reversal of 2334511534081 is 1804351154332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1975331866225 + 359179667856 = 1405465^2 + 599316^2 .
It is a cyclic number.
It is not a de Polignac number, because 2334511534081 - 213 = 2334511525889 is a prime.
It is a super-2 number, since 2×23345115340812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2334511534681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1167255767040 + 1167255767041.
It is an arithmetic number, because the mean of its divisors is an integer number (1167255767041).
Almost surely, 22334511534081 is an apocalyptic number.
It is an amenable number.
2334511534081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2334511534081 is an equidigital number, since it uses as much as digits as its factorization.
2334511534081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 2334511534081 in words is "two trillion, three hundred thirty-four billion, five hundred eleven million, five hundred thirty-four thousand, eighty-one".
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