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23400150013556 = 225850037503389
BaseRepresentation
bin1010101001000010001011…
…01000010001011001110100
310001212000212200120122000022
411110201011220101121310
511031342001400413211
6121433514105104312
74633414350204221
oct524410550213164
9101760780518008
1023400150013556
117501a47707558
12275b132a88098
131009817557094
145ac805206948
152a8a59256bdb
hex154845a11674

23400150013556 has 6 divisors (see below), whose sum is σ = 40950262523730. Its totient is φ = 11700075006776.

The previous prime is 23400150013553. The next prime is 23400150013573. The reversal of 23400150013556 is 65531005100432.

It can be written as a sum of positive squares in only one way, i.e., 23400109817956 + 40195600 = 4837366^2 + 6340^2 .

It is a super-4 number, since 4×234001500135564 (a number of 55 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23400150013553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2925018751691 + ... + 2925018751698.

It is an arithmetic number, because the mean of its divisors is an integer number (6825043753955).

Almost surely, 223400150013556 is an apocalyptic number.

It is an amenable number.

23400150013556 is a deficient number, since it is larger than the sum of its proper divisors (17550112510174).

23400150013556 is a wasteful number, since it uses less digits than its factorization.

23400150013556 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5850037503393 (or 5850037503391 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 23400150013556 its reverse (65531005100432), we get a palindrome (88931155113988).

The spelling of 23400150013556 in words is "twenty-three trillion, four hundred billion, one hundred fifty million, thirteen thousand, five hundred fifty-six".

Divisors: 1 2 4 5850037503389 11700075006778 23400150013556