Base | Representation |
---|---|
bin | 1010101001000010100010… |
… | …01101110101110011010011 |
3 | 10001212001101020101001122111 |
4 | 11110201101031311303103 |
5 | 11031342401132130342 |
6 | 121433545251450151 |
7 | 4633422230436511 |
oct | 524412115656323 |
9 | 101761336331574 |
10 | 23400344411347 |
11 | 7502037413492 |
12 | 275b187bb6957 |
13 | 10098488cc467 |
14 | 5ac822d6b4b1 |
15 | 2a8a6b356217 |
hex | 154851375cd3 |
23400344411347 has 2 divisors, whose sum is σ = 23400344411348. Its totient is φ = 23400344411346.
The previous prime is 23400344411341. The next prime is 23400344411371. The reversal of 23400344411347 is 74311444300432.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23400344411347 is a prime.
It is a super-2 number, since 2×234003444113472 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23400344411341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11700172205673 + 11700172205674.
It is an arithmetic number, because the mean of its divisors is an integer number (11700172205674).
Almost surely, 223400344411347 is an apocalyptic number.
23400344411347 is a deficient number, since it is larger than the sum of its proper divisors (1).
23400344411347 is an equidigital number, since it uses as much as digits as its factorization.
23400344411347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 40.
Adding to 23400344411347 its reverse (74311444300432), we get a palindrome (97711788711779).
The spelling of 23400344411347 in words is "twenty-three trillion, four hundred billion, three hundred forty-four million, four hundred eleven thousand, three hundred forty-seven".
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