Base | Representation |
---|---|
bin | 1010101001000011110000… |
… | …10111011101010111000111 |
3 | 10001212010002000022121210121 |
4 | 11110201320113131113013 |
5 | 11031400222304302403 |
6 | 121434134354002411 |
7 | 4633444424432020 |
oct | 524417027352707 |
9 | 101763060277717 |
10 | 23401001244103 |
11 | 750234415967a |
12 | 275b32bb76407 |
13 | 1009921a064b2 |
14 | 5ac8862a9c47 |
15 | 2a8aa8d4d3bd |
hex | 1548785dd5c7 |
23401001244103 has 4 divisors (see below), whose sum is σ = 26744001421840. Its totient is φ = 20058001066368.
The previous prime is 23401001244041. The next prime is 23401001244163. The reversal of 23401001244103 is 30144210010432.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23401001244103 - 29 = 23401001243591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23401001244163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1671500088858 + ... + 1671500088871.
It is an arithmetic number, because the mean of its divisors is an integer number (6686000355460).
Almost surely, 223401001244103 is an apocalyptic number.
23401001244103 is a deficient number, since it is larger than the sum of its proper divisors (3343000177737).
23401001244103 is an equidigital number, since it uses as much as digits as its factorization.
23401001244103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3343000177736.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 23401001244103 its reverse (30144210010432), we get a palindrome (53545211254535).
The spelling of 23401001244103 in words is "twenty-three trillion, four hundred one billion, one million, two hundred forty-four thousand, one hundred three".
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