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2340120301121 is a prime number
BaseRepresentation
bin100010000011011010000…
…010100000111001000001
322021201021000012100022202
4202003122002200321001
5301320031244113441
64551011511242545
7331032235235351
oct42033202407101
98251230170282
102340120301121
118224919a3139
12319645679455
1313c898346515
1481396156b61
1540d129d819b
hex220da0a0e41

2340120301121 has 2 divisors, whose sum is σ = 2340120301122. Its totient is φ = 2340120301120.

The previous prime is 2340120301117. The next prime is 2340120301147. The reversal of 2340120301121 is 1211030210432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1700937640000 + 639182661121 = 1304200^2 + 799489^2 .

It is a cyclic number.

It is not a de Polignac number, because 2340120301121 - 22 = 2340120301117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2340120301093 and 2340120301102.

It is not a weakly prime, because it can be changed into another prime (2340120301111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170060150560 + 1170060150561.

It is an arithmetic number, because the mean of its divisors is an integer number (1170060150561).

Almost surely, 22340120301121 is an apocalyptic number.

It is an amenable number.

2340120301121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2340120301121 is an equidigital number, since it uses as much as digits as its factorization.

2340120301121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2340120301121 its reverse (1211030210432), we get a palindrome (3551150511553).

The spelling of 2340120301121 in words is "two trillion, three hundred forty billion, one hundred twenty million, three hundred one thousand, one hundred twenty-one".