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234012344413 = 1509911549843
BaseRepresentation
bin1101100111110000111…
…0010000000001011101
3211101000201111210200011
43121330032100001131
512313224130010123
6255300452403221
722623021051661
oct3317416200135
9741021453604
10234012344413
119027595aa51
123942a316511
13190b4a38663
14b47d3748a1
156149460e0d
hex367c39005d

234012344413 has 4 divisors (see below), whose sum is σ = 234014045248. Its totient is φ = 234010643580.

The previous prime is 234012344389. The next prime is 234012344417. The reversal of 234012344413 is 314443210432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 234012344413 - 25 = 234012344381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (234012344417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 623931 + ... + 925912.

It is an arithmetic number, because the mean of its divisors is an integer number (58503511312).

Almost surely, 2234012344413 is an apocalyptic number.

It is an amenable number.

234012344413 is a deficient number, since it is larger than the sum of its proper divisors (1700835).

234012344413 is a wasteful number, since it uses less digits than its factorization.

234012344413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1700834.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 234012344413 its reverse (314443210432), we get a palindrome (548455554845).

The spelling of 234012344413 in words is "two hundred thirty-four billion, twelve million, three hundred forty-four thousand, four hundred thirteen".

Divisors: 1 150991 1549843 234012344413