Base | Representation |
---|---|
bin | 1101100111110000111… |
… | …0010000000000111101 |
3 | 211101000201111210121222 |
4 | 3121330032100000331 |
5 | 12313224130010011 |
6 | 255300452403125 |
7 | 22623021051614 |
oct | 3317416200075 |
9 | 741021453558 |
10 | 234012344381 |
11 | 9027595aa22 |
12 | 3942a3164a5 |
13 | 190b4a3863a |
14 | b47d37487b |
15 | 6149460ddb |
hex | 367c39003d |
234012344381 has 2 divisors, whose sum is σ = 234012344382. Its totient is φ = 234012344380.
The previous prime is 234012344297. The next prime is 234012344389. The reversal of 234012344381 is 183443210432.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 136611552100 + 97400792281 = 369610^2 + 312091^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-234012344381 is a prime.
It is a super-2 number, since 2×2340123443812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (234012344389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117006172190 + 117006172191.
It is an arithmetic number, because the mean of its divisors is an integer number (117006172191).
Almost surely, 2234012344381 is an apocalyptic number.
It is an amenable number.
234012344381 is a deficient number, since it is larger than the sum of its proper divisors (1).
234012344381 is an equidigital number, since it uses as much as digits as its factorization.
234012344381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
The spelling of 234012344381 in words is "two hundred thirty-four billion, twelve million, three hundred forty-four thousand, three hundred eighty-one".
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