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234013042131 = 3117091304307
BaseRepresentation
bin1101100111110001000…
…0111010010111010011
3211101000202211020202120
43121330100322113103
512313224314322011
6255300515345323
722623030016101
oct3317420722723
9741022736676
10234013042131
1190276297180
123942a5b2243
13190b4c210cb
14b47d4b6c71
15614954ca06
hex367c43a5d3

234013042131 has 8 divisors (see below), whose sum is σ = 340382606784. Its totient is φ = 141826086120.

The previous prime is 234013042111. The next prime is 234013042199. The reversal of 234013042131 is 131240310432.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 234013042131 - 217 = 234012911059 is a prime.

It is a super-2 number, since 2×2340130421312 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (234013042111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3545652121 + ... + 3545652186.

It is an arithmetic number, because the mean of its divisors is an integer number (42547825848).

Almost surely, 2234013042131 is an apocalyptic number.

234013042131 is a deficient number, since it is larger than the sum of its proper divisors (106369564653).

234013042131 is a wasteful number, since it uses less digits than its factorization.

234013042131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7091304321.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 234013042131 its reverse (131240310432), we get a palindrome (365253352563).

The spelling of 234013042131 in words is "two hundred thirty-four billion, thirteen million, forty-two thousand, one hundred thirty-one".

Divisors: 1 3 11 33 7091304307 21273912921 78004347377 234013042131