Base | Representation |
---|---|
bin | 1000101101111011… |
… | …1001000011000011 |
3 | 20001002100222020221 |
4 | 2023132321003003 |
5 | 14243033143021 |
6 | 1024113043511 |
7 | 111663533251 |
oct | 21336710303 |
9 | 6032328227 |
10 | 2340131011 |
11 | aa0a41079 |
12 | 553856597 |
13 | 2b3a8650a |
14 | 182b175d1 |
15 | da69c241 |
hex | 8b7b90c3 |
2340131011 has 2 divisors, whose sum is σ = 2340131012. Its totient is φ = 2340131010.
The previous prime is 2340130931. The next prime is 2340131051. The reversal of 2340131011 is 1101310432.
2340131011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2340131011 - 223 = 2331742403 is a prime.
It is not a weakly prime, because it can be changed into another prime (2340131051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170065505 + 1170065506.
It is an arithmetic number, because the mean of its divisors is an integer number (1170065506).
Almost surely, 22340131011 is an apocalyptic number.
2340131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2340131011 is an equidigital number, since it uses as much as digits as its factorization.
2340131011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 2340131011 is about 48374.9006303889. The cubic root of 2340131011 is about 1327.6391704503.
Adding to 2340131011 its reverse (1101310432), we get a palindrome (3441441443).
The spelling of 2340131011 in words is "two billion, three hundred forty million, one hundred thirty-one thousand, eleven".
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