Base | Representation |
---|---|
bin | 100010000011011010101… |
… | …100011110011011011011 |
3 | 22021201021202220012102202 |
4 | 202003122230132123123 |
5 | 301320042103113313 |
6 | 4551012543120415 |
7 | 331032430601252 |
oct | 42033254363333 |
9 | 8251252805382 |
10 | 2340131301083 |
11 | 822498126614 |
12 | 3196492a310b |
13 | 13c89a6c8284 |
14 | 813977bb799 |
15 | 40d1395c558 |
hex | 220dab1e6db |
2340131301083 has 2 divisors, whose sum is σ = 2340131301084. Its totient is φ = 2340131301082.
The previous prime is 2340131301043. The next prime is 2340131301121. The reversal of 2340131301083 is 3801031310432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2340131301083 - 218 = 2340131038939 is a prime.
It is not a weakly prime, because it can be changed into another prime (2340131301043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170065650541 + 1170065650542.
It is an arithmetic number, because the mean of its divisors is an integer number (1170065650542).
Almost surely, 22340131301083 is an apocalyptic number.
2340131301083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2340131301083 is an equidigital number, since it uses as much as digits as its factorization.
2340131301083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 2340131301083 in words is "two trillion, three hundred forty billion, one hundred thirty-one million, three hundred one thousand, eighty-three".
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