Base | Representation |
---|---|
bin | 110101001101100110110001… |
… | …101001001011000001110011 |
3 | 1010200122012002101001100120112 |
4 | 311031212301221023001303 |
5 | 221133332404024231201 |
6 | 2145424322045131535 |
7 | 100203133404060035 |
oct | 6515466151130163 |
9 | 1120565071040515 |
10 | 234031453352051 |
11 | 6862a2002589a3 |
12 | 222b8a44259bab |
13 | a0780c09ca474 |
14 | 41b127b797c55 |
15 | 1c0ca663300bb |
hex | d4d9b1a4b073 |
234031453352051 has 2 divisors, whose sum is σ = 234031453352052. Its totient is φ = 234031453352050.
The previous prime is 234031453352033. The next prime is 234031453352117. The reversal of 234031453352051 is 150253354130432.
234031453352051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 234031453352051 - 210 = 234031453351027 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (234031453351051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117015726676025 + 117015726676026.
It is an arithmetic number, because the mean of its divisors is an integer number (117015726676026).
Almost surely, 2234031453352051 is an apocalyptic number.
234031453352051 is a deficient number, since it is larger than the sum of its proper divisors (1).
234031453352051 is an equidigital number, since it uses as much as digits as its factorization.
234031453352051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 41.
The spelling of 234031453352051 in words is "two hundred thirty-four trillion, thirty-one billion, four hundred fifty-three million, three hundred fifty-two thousand, fifty-one".
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