Base | Representation |
---|---|
bin | 1010101001001100000100… |
… | …01100100100111111110110 |
3 | 10001212112120211101100211012 |
4 | 11110212002030210333312 |
5 | 11031433341022200004 |
6 | 121440153112512222 |
7 | 4633663101024326 |
oct | 524460214447766 |
9 | 101775524340735 |
10 | 23405461131254 |
11 | 75042226a1924 |
12 | 27601756ab672 |
13 | 100a1829a6c87 |
14 | 5acb8a733286 |
15 | 2a8c6a66646e |
hex | 154982324ff6 |
23405461131254 has 8 divisors (see below), whose sum is σ = 35113012286040. Its totient is φ = 11701123702576.
The previous prime is 23405461131253. The next prime is 23405461131257. The reversal of 23405461131254 is 45213116450432.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×234054611312542 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23405461131253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803413319 + ... + 803442450.
It is an arithmetic number, because the mean of its divisors is an integer number (4389126535755).
Almost surely, 223405461131254 is an apocalyptic number.
23405461131254 is a deficient number, since it is larger than the sum of its proper divisors (11707551154786).
23405461131254 is a wasteful number, since it uses less digits than its factorization.
23405461131254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1606863054.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 23405461131254 its reverse (45213116450432), we get a palindrome (68618577581686).
The spelling of 23405461131254 in words is "twenty-three trillion, four hundred five billion, four hundred sixty-one million, one hundred thirty-one thousand, two hundred fifty-four".
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