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234096518437 = 290980473193
BaseRepresentation
bin1101101000000100111…
…1010110010100100101
3211101020120220021201121
43122001033112110211
512313412202042222
6255313100453541
722625062401205
oct3320117262445
9741216807647
10234096518437
1190309422161
123945254a2b1
13190c92ca882
14b48a606405
156151a3b5c7
hex36813d6525

234096518437 has 4 divisors (see below), whose sum is σ = 234176994540. Its totient is φ = 234016042336.

The previous prime is 234096518401. The next prime is 234096518443. The reversal of 234096518437 is 734815690432.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 95415503236 + 138681015201 = 308894^2 + 372399^2 .

It is a cyclic number.

It is not a de Polignac number, because 234096518437 - 215 = 234096485669 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (234096513437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40233688 + ... + 40239505.

It is an arithmetic number, because the mean of its divisors is an integer number (58544248635).

It is a 1-persistent number, because it is pandigital, but 2⋅234096518437 = 468193036874 is not.

Almost surely, 2234096518437 is an apocalyptic number.

It is an amenable number.

234096518437 is a deficient number, since it is larger than the sum of its proper divisors (80476103).

234096518437 is an equidigital number, since it uses as much as digits as its factorization.

234096518437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80476102.

The product of its (nonzero) digits is 4354560, while the sum is 52.

The spelling of 234096518437 in words is "two hundred thirty-four billion, ninety-six million, five hundred eighteen thousand, four hundred thirty-seven".

Divisors: 1 2909 80473193 234096518437