Base | Representation |
---|---|
bin | 110101001110110011110000… |
… | …101011001001010100001011 |
3 | 1010200221002110012220221201120 |
4 | 311032303300223021110023 |
5 | 221141211201443300210 |
6 | 2145530312331450323 |
7 | 100212121010225634 |
oct | 6516636053112413 |
9 | 1120832405827646 |
10 | 234114115212555 |
11 | 68661269771196 |
12 | 22310a735b69a3 |
13 | a082b35453c66 |
14 | 41b527dc7888b |
15 | 1c0eca334d270 |
hex | d4ecf0ac950b |
234114115212555 has 32 divisors (see below), whose sum is σ = 396785126919744. Its totient is φ = 117466246250496.
The previous prime is 234114115212541. The next prime is 234114115212563. The reversal of 234114115212555 is 555212511411432.
234114115212555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 234114115212555 - 27 = 234114115212427 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 194158102 + ... + 195360171.
It is an arithmetic number, because the mean of its divisors is an integer number (12399535216242).
Almost surely, 2234114115212555 is an apocalyptic number.
234114115212555 is a deficient number, since it is larger than the sum of its proper divisors (162671011707189).
234114115212555 is a wasteful number, since it uses less digits than its factorization.
234114115212555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 389520655.
The product of its digits is 240000, while the sum is 42.
Adding to 234114115212555 its reverse (555212511411432), we get a palindrome (789326626623987).
The spelling of 234114115212555 in words is "two hundred thirty-four trillion, one hundred fourteen billion, one hundred fifteen million, two hundred twelve thousand, five hundred fifty-five".
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