2341222221433 has 2 divisors, whose sum is σ = 2341222221434. Its totient is φ = 2341222221432.

The previous prime is 2341222221343. The next prime is 2341222221469. The reversal of 2341222221433 is 3341222221432.

Together with previous prime (2341222221343) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2312929972224 + 28292249209 = 1520832^2 + 168203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2341222221433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2341222221395 and 2341222221404.

It is not a weakly prime, because it can be changed into another prime (2341222291433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170611110716 + 1170611110717.

It is an arithmetic number, because the mean of its divisors is an integer number (1170611110717).

Almost surely, 2^{2341222221433} is an apocalyptic number.

It is an amenable number.

2341222221433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2341222221433 is an equidigital number, since it uses as much as digits as its factorization.

2341222221433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27648, while the sum is 31.

Adding to 2341222221433 its reverse (3341222221432), we get a palindrome (5682444442865).

Subtracting 2341222221433 from its reverse (3341222221432), we obtain a palindrome (999999999999).

The spelling of 2341222221433 in words is "two trillion, three hundred forty-one billion, two hundred twenty-two million, two hundred twenty-one thousand, four hundred thirty-three".