Base | Representation |
---|---|
bin | 1010101001011001010000… |
… | …01001001110001010011011 |
3 | 10001220012212011222011112021 |
4 | 11110230220021032022123 |
5 | 11032042340300031233 |
6 | 121443323354355311 |
7 | 4634333400312061 |
oct | 524545011161233 |
9 | 101805764864467 |
10 | 23412540236443 |
11 | 7507225666386 |
12 | 276161042bb37 |
13 | 100aa404b8c07 |
14 | 5ad25c9a2031 |
15 | 2a9031da8e2d |
hex | 154b2824e29b |
23412540236443 has 2 divisors, whose sum is σ = 23412540236444. Its totient is φ = 23412540236442.
The previous prime is 23412540236419. The next prime is 23412540236461. The reversal of 23412540236443 is 34463204521432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23412540236443 - 25 = 23412540236411 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23412540236443.
It is not a weakly prime, because it can be changed into another prime (23412540266443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11706270118221 + 11706270118222.
It is an arithmetic number, because the mean of its divisors is an integer number (11706270118222).
Almost surely, 223412540236443 is an apocalyptic number.
23412540236443 is a deficient number, since it is larger than the sum of its proper divisors (1).
23412540236443 is an equidigital number, since it uses as much as digits as its factorization.
23412540236443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1658880, while the sum is 43.
Adding to 23412540236443 its reverse (34463204521432), we get a palindrome (57875744757875).
The spelling of 23412540236443 in words is "twenty-three trillion, four hundred twelve billion, five hundred forty million, two hundred thirty-six thousand, four hundred forty-three".
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