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2341413433441 is a prime number
BaseRepresentation
bin100010000100100111000…
…111011011000001100001
322021211121010110021101101
4202010213013123001201
5301330203314332231
64551344103434401
7331106256543415
oct42044707330141
98254533407341
102341413433441
11822a9592a635
12319946755a01
1313ca43218584
1481479baad45
1540d8b2bd661
hex221271db061

2341413433441 has 2 divisors, whose sum is σ = 2341413433442. Its totient is φ = 2341413433440.

The previous prime is 2341413433409. The next prime is 2341413433451. The reversal of 2341413433441 is 1443343141432.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2221053702400 + 120359731041 = 1490320^2 + 346929^2 .

It is a cyclic number.

It is not a de Polignac number, because 2341413433441 - 25 = 2341413433409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2341413433441.

It is not a weakly prime, because it can be changed into another prime (2341413433451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170706716720 + 1170706716721.

It is an arithmetic number, because the mean of its divisors is an integer number (1170706716721).

Almost surely, 22341413433441 is an apocalyptic number.

It is an amenable number.

2341413433441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2341413433441 is an equidigital number, since it uses as much as digits as its factorization.

2341413433441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 165888, while the sum is 37.

Adding to 2341413433441 its reverse (1443343141432), we get a palindrome (3784756574873).

The spelling of 2341413433441 in words is "two trillion, three hundred forty-one billion, four hundred thirteen million, four hundred thirty-three thousand, four hundred forty-one".