Base | Representation |
---|---|
bin | 100010000110001101000… |
… | …100110011111100101011 |
3 | 22022000000100020100001011 |
4 | 202012031010303330223 |
5 | 301342204222301011 |
6 | 4552225531404351 |
7 | 331166540411251 |
oct | 42061504637453 |
9 | 8260010210034 |
10 | 2343124025131 |
11 | 82379347747a |
12 | 31a1435b36b7 |
13 | 13cc56732ac6 |
14 | 8159d04c5d1 |
15 | 40e3b565621 |
hex | 2218d133f2b |
2343124025131 has 2 divisors, whose sum is σ = 2343124025132. Its totient is φ = 2343124025130.
The previous prime is 2343124025117. The next prime is 2343124025183. The reversal of 2343124025131 is 1315204213432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2343124025131 - 219 = 2343123500843 is a prime.
It is a super-2 number, since 2×23431240251312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2343124025093 and 2343124025102.
It is not a weakly prime, because it can be changed into another prime (2343124023131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1171562012565 + 1171562012566.
It is an arithmetic number, because the mean of its divisors is an integer number (1171562012566).
Almost surely, 22343124025131 is an apocalyptic number.
2343124025131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2343124025131 is an equidigital number, since it uses as much as digits as its factorization.
2343124025131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 2343124025131 its reverse (1315204213432), we get a palindrome (3658328238563).
The spelling of 2343124025131 in words is "two trillion, three hundred forty-three billion, one hundred twenty-four million, twenty-five thousand, one hundred thirty-one".
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