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23433122137 is a prime number
BaseRepresentation
bin10101110100101110…
…010001000101011001
32020111002112221110111
4111310232101011121
5340442334402022
614433125044321
71456460152225
oct256456210531
966432487414
1023433122137
119a35428547
12465b8566a1
132295a29859
1411c4235785
15922367477
hex574b91159

23433122137 has 2 divisors, whose sum is σ = 23433122138. Its totient is φ = 23433122136.

The previous prime is 23433122071. The next prime is 23433122191. The reversal of 23433122137 is 73122133432.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21779561241 + 1653560896 = 147579^2 + 40664^2 .

It is a cyclic number.

It is not a de Polignac number, because 23433122137 - 223 = 23424733529 is a prime.

It is a super-2 number, since 2×234331221372 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23433122099 and 23433122108.

It is not a weakly prime, because it can be changed into another prime (23433128137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11716561068 + 11716561069.

It is an arithmetic number, because the mean of its divisors is an integer number (11716561069).

Almost surely, 223433122137 is an apocalyptic number.

It is an amenable number.

23433122137 is a deficient number, since it is larger than the sum of its proper divisors (1).

23433122137 is an equidigital number, since it uses as much as digits as its factorization.

23433122137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18144, while the sum is 31.

Adding to 23433122137 its reverse (73122133432), we get a palindrome (96555255569).

The spelling of 23433122137 in words is "twenty-three billion, four hundred thirty-three million, one hundred twenty-two thousand, one hundred thirty-seven".