Base | Representation |
---|---|
bin | 1000101110101101… |
… | …1100010011011011 |
3 | 20001022120010110211 |
4 | 2023223130103123 |
5 | 14244403434042 |
6 | 1024311351551 |
7 | 112033515424 |
oct | 21353342333 |
9 | 6038503424 |
10 | 2343421147 |
11 | aa2888aa1 |
12 | 5549825b7 |
13 | 2b4668c42 |
14 | 18333264b |
15 | daaec017 |
hex | 8badc4db |
2343421147 has 2 divisors, whose sum is σ = 2343421148. Its totient is φ = 2343421146.
The previous prime is 2343421127. The next prime is 2343421153. The reversal of 2343421147 is 7411243432.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2343421147 is a prime.
It is not a weakly prime, because it can be changed into another prime (2343421127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1171710573 + 1171710574.
It is an arithmetic number, because the mean of its divisors is an integer number (1171710574).
Almost surely, 22343421147 is an apocalyptic number.
2343421147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2343421147 is an equidigital number, since it uses as much as digits as its factorization.
2343421147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 16128, while the sum is 31.
The square root of 2343421147 is about 48408.8953292677. The cubic root of 2343421147 is about 1328.2610826242.
Adding to 2343421147 its reverse (7411243432), we get a palindrome (9754664579).
The spelling of 2343421147 in words is "two billion, three hundred forty-three million, four hundred twenty-one thousand, one hundred forty-seven".
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