Base | Representation |
---|---|
bin | 1010101010010010001111… |
… | …01100000100001100001011 |
3 | 10002000010211022222100021212 |
4 | 11111021013230010030023 |
5 | 11033043014331013103 |
6 | 121505343250123335 |
7 | 4636465502104241 |
oct | 525110754041413 |
9 | 102003738870255 |
10 | 23443134235403 |
11 | 75191a5129643 |
12 | 276752a28054b |
13 | 10108a795828c |
14 | 5b0921c70791 |
15 | 2a9c22c177d8 |
hex | 155247b0430b |
23443134235403 has 2 divisors, whose sum is σ = 23443134235404. Its totient is φ = 23443134235402.
The previous prime is 23443134235373. The next prime is 23443134235489. The reversal of 23443134235403 is 30453243134432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23443134235403 - 220 = 23443133186827 is a prime.
It is not a weakly prime, because it can be changed into another prime (23443134231403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11721567117701 + 11721567117702.
It is an arithmetic number, because the mean of its divisors is an integer number (11721567117702).
Almost surely, 223443134235403 is an apocalyptic number.
23443134235403 is a deficient number, since it is larger than the sum of its proper divisors (1).
23443134235403 is an equidigital number, since it uses as much as digits as its factorization.
23443134235403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 41.
Adding to 23443134235403 its reverse (30453243134432), we get a palindrome (53896377369835).
The spelling of 23443134235403 in words is "twenty-three trillion, four hundred forty-three billion, one hundred thirty-four million, two hundred thirty-five thousand, four hundred three".
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