Base | Representation |
---|---|
bin | 1010101010010010011000… |
… | …01101001111011100011001 |
3 | 10002000011000121121200011202 |
4 | 11111021030031033130121 |
5 | 11033043143232303423 |
6 | 121505354555003545 |
7 | 4636500412331162 |
oct | 525111415173431 |
9 | 102004017550152 |
10 | 23443210041113 |
11 | 75192339a5595 |
12 | 276754b7395b5 |
13 | 10108ba57a525 |
14 | 5b092bd64769 |
15 | 2a9c296dd728 |
hex | 15524c34f719 |
23443210041113 has 2 divisors, whose sum is σ = 23443210041114. Its totient is φ = 23443210041112.
The previous prime is 23443210041077. The next prime is 23443210041151. The reversal of 23443210041113 is 31114001234432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20970098393344 + 2473111647769 = 4579312^2 + 1572613^2 .
It is a cyclic number.
It is not a de Polignac number, because 23443210041113 - 226 = 23443142932249 is a prime.
It is not a weakly prime, because it can be changed into another prime (23443210049113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11721605020556 + 11721605020557.
It is an arithmetic number, because the mean of its divisors is an integer number (11721605020557).
Almost surely, 223443210041113 is an apocalyptic number.
It is an amenable number.
23443210041113 is a deficient number, since it is larger than the sum of its proper divisors (1).
23443210041113 is an equidigital number, since it uses as much as digits as its factorization.
23443210041113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 23443210041113 its reverse (31114001234432), we get a palindrome (54557211275545).
The spelling of 23443210041113 in words is "twenty-three trillion, four hundred forty-three billion, two hundred ten million, forty-one thousand, one hundred thirteen".
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