Base | Representation |
---|---|
bin | 1010101011101111101110… |
… | …00110010000010111000011 |
3 | 10002011221100222122110010211 |
4 | 11111313313012100113003 |
5 | 11034403310332112201 |
6 | 121544403310534551 |
7 | 4643223262011502 |
oct | 525676706202703 |
9 | 102157328573124 |
10 | 23493321754051 |
11 | 753850972a186 |
12 | 27751b5b07457 |
13 | 1015545502186 |
14 | 5b3123454839 |
15 | 2ab1adc9d651 |
hex | 155df71905c3 |
23493321754051 has 2 divisors, whose sum is σ = 23493321754052. Its totient is φ = 23493321754050.
The previous prime is 23493321754013. The next prime is 23493321754079. The reversal of 23493321754051 is 15045712339432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23493321754051 - 223 = 23493313365443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23493321753986 and 23493321754004.
It is not a weakly prime, because it can be changed into another prime (23493321754351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11746660877025 + 11746660877026.
It is an arithmetic number, because the mean of its divisors is an integer number (11746660877026).
Almost surely, 223493321754051 is an apocalyptic number.
23493321754051 is a deficient number, since it is larger than the sum of its proper divisors (1).
23493321754051 is an equidigital number, since it uses as much as digits as its factorization.
23493321754051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 49.
The spelling of 23493321754051 in words is "twenty-three trillion, four hundred ninety-three billion, three hundred twenty-one million, seven hundred fifty-four thousand, fifty-one".
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