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2350013354041 is a prime number
BaseRepresentation
bin100010001100100111101…
…101100001000000111001
322022122210110201111122011
4202030213231201000321
5302000311404312131
64555325313525521
7331532343632263
oct42144755410071
98278713644564
102350013354041
118266a9301231
1231b5468738a1
131407b3b2a0a2
1481a53ddab33
15411e12bd0b1
hex22327b61039

2350013354041 has 2 divisors, whose sum is σ = 2350013354042. Its totient is φ = 2350013354040.

The previous prime is 2350013354023. The next prime is 2350013354053. The reversal of 2350013354041 is 1404533100532.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1871481456441 + 478531897600 = 1368021^2 + 691760^2 .

It is a cyclic number.

It is not a de Polignac number, because 2350013354041 - 27 = 2350013353913 is a prime.

It is a super-2 number, since 2×23500133540412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2350013353994 and 2350013354012.

It is not a weakly prime, because it can be changed into another prime (2350013354071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1175006677020 + 1175006677021.

It is an arithmetic number, because the mean of its divisors is an integer number (1175006677021).

Almost surely, 22350013354041 is an apocalyptic number.

It is an amenable number.

2350013354041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2350013354041 is an equidigital number, since it uses as much as digits as its factorization.

2350013354041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 2350013354041 its reverse (1404533100532), we get a palindrome (3754546454573).

The spelling of 2350013354041 in words is "two trillion, three hundred fifty billion, thirteen million, three hundred fifty-four thousand, forty-one".