Base | Representation |
---|---|
bin | 1010101011111110100111… |
… | …00011010011010010100010 |
3 | 10002012201000001221211100121 |
4 | 11111333103203103102202 |
5 | 11040021143210314132 |
6 | 121552204420510454 |
7 | 4643625334145404 |
oct | 525772343232242 |
9 | 102181001854317 |
10 | 23501315323042 |
11 | 7540940904947 |
12 | 2776866b4b42a |
13 | 101621a60305b |
14 | 5b3680d26b74 |
15 | 2ab4ca928497 |
hex | 155fd38d34a2 |
23501315323042 has 4 divisors (see below), whose sum is σ = 35251972984566. Its totient is φ = 11750657661520.
The previous prime is 23501315323033. The next prime is 23501315323049. The reversal of 23501315323042 is 24032351310532.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 23288915087881 + 212400235161 = 4825859^2 + 460869^2 .
It is a super-3 number, since 3×235013153230423 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 23501315322989 and 23501315323007.
It is not an unprimeable number, because it can be changed into a prime (23501315323049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5875328830759 + ... + 5875328830762.
Almost surely, 223501315323042 is an apocalyptic number.
23501315323042 is a deficient number, since it is larger than the sum of its proper divisors (11750657661524).
23501315323042 is a wasteful number, since it uses less digits than its factorization.
23501315323042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11750657661523.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 23501315323042 its reverse (24032351310532), we get a palindrome (47533666633574).
The spelling of 23501315323042 in words is "twenty-three trillion, five hundred one billion, three hundred fifteen million, three hundred twenty-three thousand, forty-two".
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