Base | Representation |
---|---|
bin | 100010001110100110011… |
… | …110011111010110011001 |
3 | 22022212021200121111010012 |
4 | 202032212132133112121 |
5 | 302014140332341442 |
6 | 5000320325531305 |
7 | 331636140102425 |
oct | 42164636372631 |
9 | 8285250544105 |
10 | 2352140121497 |
11 | 82759a862091 |
12 | 31ba3ab73b35 |
13 | 140a6262a77a |
14 | 81bb6653b85 |
15 | 412b7d71582 |
hex | 223a679f599 |
2352140121497 has 2 divisors, whose sum is σ = 2352140121498. Its totient is φ = 2352140121496.
The previous prime is 2352140121449. The next prime is 2352140121509. The reversal of 2352140121497 is 7941210412532.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1780972989961 + 571167131536 = 1334531^2 + 755756^2 .
It is a cyclic number.
It is not a de Polignac number, because 2352140121497 - 28 = 2352140121241 is a prime.
It is not a weakly prime, because it can be changed into another prime (2352140127497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1176070060748 + 1176070060749.
It is an arithmetic number, because the mean of its divisors is an integer number (1176070060749).
Almost surely, 22352140121497 is an apocalyptic number.
It is an amenable number.
2352140121497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2352140121497 is an equidigital number, since it uses as much as digits as its factorization.
2352140121497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 2352140121497 in words is "two trillion, three hundred fifty-two billion, one hundred forty million, one hundred twenty-one thousand, four hundred ninety-seven".
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