Base | Representation |
---|---|
bin | 110101100001101011011001… |
… | …000111101000111001010011 |
3 | 1010212112001102102101212222121 |
4 | 311201223121013220321103 |
5 | 221323432304314332042 |
6 | 2152402121214115111 |
7 | 100404604040321224 |
oct | 6541533107507123 |
9 | 1125461372355877 |
10 | 235410800152147 |
11 | 690111835a2434 |
12 | 224a02347aba97 |
13 | a1481b27c5099 |
14 | 421bd2d04724b |
15 | 1c338961e8367 |
hex | d61ad91e8e53 |
235410800152147 has 2 divisors, whose sum is σ = 235410800152148. Its totient is φ = 235410800152146.
The previous prime is 235410800152141. The next prime is 235410800152337. The reversal of 235410800152147 is 741251008014532.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-235410800152147 is a prime.
It is not a weakly prime, because it can be changed into another prime (235410800152141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117705400076073 + 117705400076074.
It is an arithmetic number, because the mean of its divisors is an integer number (117705400076074).
Almost surely, 2235410800152147 is an apocalyptic number.
235410800152147 is a deficient number, since it is larger than the sum of its proper divisors (1).
235410800152147 is an equidigital number, since it uses as much as digits as its factorization.
235410800152147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 43.
Adding to 235410800152147 its reverse (741251008014532), we get a palindrome (976661808166679).
The spelling of 235410800152147 in words is "two hundred thirty-five trillion, four hundred ten billion, eight hundred million, one hundred fifty-two thousand, one hundred forty-seven".
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