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235444352514433 is a prime number
BaseRepresentation
bin110101100010001010101000…
…111111101111100110000001
31010212122021000202002111022021
4311202022220333233212001
5221330010013220430213
62152425350425441441
7100410202353563356
oct6542125077574601
91125567022074267
10235444352514433
1169024430a77867
12224a6839340281
13a14b3cbb2b1aa
14421d7d31a062d
151c346abb23d8d
hexd622a8fef981

235444352514433 has 2 divisors, whose sum is σ = 235444352514434. Its totient is φ = 235444352514432.

The previous prime is 235444352514419. The next prime is 235444352514509. The reversal of 235444352514433 is 334415253444532.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 235091597293809 + 352755220624 = 15332697^2 + 593932^2 .

It is a cyclic number.

It is not a de Polignac number, because 235444352514433 - 213 = 235444352506241 is a prime.

It is a super-2 number, since 2×2354443525144332 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (235444352514533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117722176257216 + 117722176257217.

It is an arithmetic number, because the mean of its divisors is an integer number (117722176257217).

Almost surely, 2235444352514433 is an apocalyptic number.

It is an amenable number.

235444352514433 is a deficient number, since it is larger than the sum of its proper divisors (1).

235444352514433 is an equidigital number, since it uses as much as digits as its factorization.

235444352514433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472000, while the sum is 52.

The spelling of 235444352514433 in words is "two hundred thirty-five trillion, four hundred forty-four billion, three hundred fifty-two million, five hundred fourteen thousand, four hundred thirty-three".