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23956172994433 is a prime number
BaseRepresentation
bin1010111001001101110110…
…01011100111011110000001
310010211012001212220122101111
411130212323023213132001
511114444220241310213
6122541151451203321
75021530204440421
oct534467313473601
9103735055818344
1023956172994433
1176a6835134749
12282aa49a46541
13104a0991c8784
145cb6b0a2c481
152b824d3a6a3d
hex15c9bb2e7781

23956172994433 has 2 divisors, whose sum is σ = 23956172994434. Its totient is φ = 23956172994432.

The previous prime is 23956172994421. The next prime is 23956172994443. The reversal of 23956172994433 is 33449927165932.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18329632441344 + 5626540553089 = 4281312^2 + 2372033^2 .

It is a cyclic number.

It is not a de Polignac number, because 23956172994433 - 225 = 23956139440001 is a prime.

It is not a weakly prime, because it can be changed into another prime (23956172994443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11978086497216 + 11978086497217.

It is an arithmetic number, because the mean of its divisors is an integer number (11978086497217).

Almost surely, 223956172994433 is an apocalyptic number.

It is an amenable number.

23956172994433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23956172994433 is an equidigital number, since it uses as much as digits as its factorization.

23956172994433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 264539520, while the sum is 67.

The spelling of 23956172994433 in words is "twenty-three trillion, nine hundred fifty-six billion, one hundred seventy-two million, nine hundred ninety-four thousand, four hundred thirty-three".