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240012741131 is a prime number
BaseRepresentation
bin1101111110000111011…
…1111100101000001011
3211221111220022112112122
43133201313330220023
512413021230204011
6302132122001455
723224511431652
oct3374167745013
9757456275478
10240012741131
1192874a318a9
123a62394628b
131982cc12b67
14b88c248199
15639b1263db
hex37e1dfca0b

240012741131 has 2 divisors, whose sum is σ = 240012741132. Its totient is φ = 240012741130.

The previous prime is 240012741119. The next prime is 240012741263. The reversal of 240012741131 is 131147210042.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-240012741131 is a prime.

It is a super-2 number, since 2×2400127411312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 240012741131.

It is not a weakly prime, because it can be changed into another prime (240012341131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120006370565 + 120006370566.

It is an arithmetic number, because the mean of its divisors is an integer number (120006370566).

Almost surely, 2240012741131 is an apocalyptic number.

240012741131 is a deficient number, since it is larger than the sum of its proper divisors (1).

240012741131 is an equidigital number, since it uses as much as digits as its factorization.

240012741131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 240012741131 its reverse (131147210042), we get a palindrome (371159951173).

The spelling of 240012741131 in words is "two hundred forty billion, twelve million, seven hundred forty-one thousand, one hundred thirty-one".