Base | Representation |
---|---|
bin | 100010111100000111100… |
… | …010100010101110100001 |
3 | 22111112102201221211102112 |
4 | 202330013202202232201 |
5 | 303314233340322423 |
6 | 5035002113525105 |
7 | 335316226404053 |
oct | 42740742425641 |
9 | 8445381854375 |
10 | 2401013214113 |
11 | 84629a401a18 |
12 | 3293ba573795 |
13 | 145550a88397 |
14 | 842d143d8d3 |
15 | 426c8817a78 |
hex | 22f078a2ba1 |
2401013214113 has 2 divisors, whose sum is σ = 2401013214114. Its totient is φ = 2401013214112.
The previous prime is 2401013213993. The next prime is 2401013214137. The reversal of 2401013214113 is 3114123101042.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2014605519424 + 386407694689 = 1419368^2 + 621617^2 .
It is a cyclic number.
It is not a de Polignac number, because 2401013214113 - 28 = 2401013213857 is a prime.
It is not a weakly prime, because it can be changed into another prime (2401013216113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1200506607056 + 1200506607057.
It is an arithmetic number, because the mean of its divisors is an integer number (1200506607057).
Almost surely, 22401013214113 is an apocalyptic number.
It is an amenable number.
2401013214113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2401013214113 is an equidigital number, since it uses as much as digits as its factorization.
2401013214113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2401013214113 its reverse (3114123101042), we get a palindrome (5515136315155).
The spelling of 2401013214113 in words is "two trillion, four hundred one billion, thirteen million, two hundred fourteen thousand, one hundred thirteen".
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