Base | Representation |
---|---|
bin | 100010111100010101000… |
… | …101001100000011100111 |
3 | 22111120000120110002000110 |
4 | 202330111011030003213 |
5 | 303320220020300403 |
6 | 5035040431144103 |
7 | 335324655426636 |
oct | 42742505140347 |
9 | 8446016402013 |
10 | 2401240400103 |
11 | 8463a6673136 |
12 | 329462675033 |
13 | 145588b7086c |
14 | 8431369b51d |
15 | 426dd742103 |
hex | 22f1514c0e7 |
2401240400103 has 64 divisors (see below), whose sum is σ = 3415832801280. Its totient is φ = 1497983155200.
The previous prime is 2401240400081. The next prime is 2401240400123. The reversal of 2401240400103 is 3010040421042.
It is not a de Polignac number, because 2401240400103 - 221 = 2401238302951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2401240400103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2401240400123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 497045898 + ... + 497050728.
It is an arithmetic number, because the mean of its divisors is an integer number (53372387520).
Almost surely, 22401240400103 is an apocalyptic number.
2401240400103 is a deficient number, since it is larger than the sum of its proper divisors (1014592401177).
2401240400103 is a wasteful number, since it uses less digits than its factorization.
2401240400103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6280.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 2401240400103 its reverse (3010040421042), we get a palindrome (5411280821145).
The spelling of 2401240400103 in words is "two trillion, four hundred one billion, two hundred forty million, four hundred thousand, one hundred three".
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