Base | Representation |
---|---|
bin | 100010111100011011101… |
… | …111011000010000001011 |
3 | 22111120022100200012120110 |
4 | 202330123233120100023 |
5 | 303320432120422103 |
6 | 5035055501525403 |
7 | 335330513156562 |
oct | 42743357302013 |
9 | 8446270605513 |
10 | 2401352123403 |
11 | 846453741542 |
12 | 329493b73863 |
13 | 1455a605a41c |
14 | 84324460bd9 |
15 | 426e8460403 |
hex | 22f1bbd840b |
2401352123403 has 64 divisors (see below), whose sum is σ = 3590309836800. Its totient is φ = 1419756011520.
The previous prime is 2401352123383. The next prime is 2401352123431. The reversal of 2401352123403 is 3043212531042.
2401352123403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2401352123403 - 29 = 2401352122891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2401352123003) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 107340603 + ... + 107362971.
It is an arithmetic number, because the mean of its divisors is an integer number (56098591200).
Almost surely, 22401352123403 is an apocalyptic number.
2401352123403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2401352123403 is a deficient number, since it is larger than the sum of its proper divisors (1188957713397).
2401352123403 is a wasteful number, since it uses less digits than its factorization.
2401352123403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23772.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 2401352123403 its reverse (3043212531042), we get a palindrome (5444564654445).
The spelling of 2401352123403 in words is "two trillion, four hundred one billion, three hundred fifty-two million, one hundred twenty-three thousand, four hundred three".
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