Base | Representation |
---|---|
bin | 100010111111000010001… |
… | …011000111101010001011 |
3 | 22111211111221212020020122 |
4 | 202333002023013222023 |
5 | 303342141432211243 |
6 | 5040240530213455 |
7 | 335456640223532 |
oct | 42770213075213 |
9 | 8454457766218 |
10 | 2404144413323 |
11 | 847656933264 |
12 | 329b3312428b |
13 | 14592c6b8193 |
14 | 8450b239319 |
15 | 4280d675668 |
hex | 22fc22c7a8b |
2404144413323 has 2 divisors, whose sum is σ = 2404144413324. Its totient is φ = 2404144413322.
The previous prime is 2404144413227. The next prime is 2404144413343. The reversal of 2404144413323 is 3233144414042.
2404144413323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2404144413323 - 224 = 2404127636107 is a prime.
It is a super-2 number, since 2×24041444133232 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2404144413343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1202072206661 + 1202072206662.
It is an arithmetic number, because the mean of its divisors is an integer number (1202072206662).
Almost surely, 22404144413323 is an apocalyptic number.
2404144413323 is a deficient number, since it is larger than the sum of its proper divisors (1).
2404144413323 is an equidigital number, since it uses as much as digits as its factorization.
2404144413323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 2404144413323 its reverse (3233144414042), we get a palindrome (5637288827365).
The spelling of 2404144413323 in words is "two trillion, four hundred four billion, one hundred forty-four million, four hundred thirteen thousand, three hundred twenty-three".
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