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240554231312441 is a prime number
BaseRepresentation
bin110110101100100001100101…
…100000011011000000111001
31011112201202111222112220012212
4312230201211200123000321
5223012220031203444231
62211341031022144505
7101445320046660434
oct6654414540330071
91145652458486185
10240554231312441
116a7145273815a2
1222b91031422135
13a42c2222642a7
144358c5b9ba81b
151cc257a99b42b
hexdac86581b039

240554231312441 has 2 divisors, whose sum is σ = 240554231312442. Its totient is φ = 240554231312440.

The previous prime is 240554231312411. The next prime is 240554231312449. The reversal of 240554231312441 is 144213132455042.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 240481315651600 + 72915660841 = 15507460^2 + 270029^2 .

It is a cyclic number.

It is not a de Polignac number, because 240554231312441 - 210 = 240554231311417 is a prime.

It is a super-2 number, since 2×2405542313124412 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (240554231312449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120277115656220 + 120277115656221.

It is an arithmetic number, because the mean of its divisors is an integer number (120277115656221).

Almost surely, 2240554231312441 is an apocalyptic number.

It is an amenable number.

240554231312441 is a deficient number, since it is larger than the sum of its proper divisors (1).

240554231312441 is an equidigital number, since it uses as much as digits as its factorization.

240554231312441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 240554231312441 its reverse (144213132455042), we get a palindrome (384767363767483).

The spelling of 240554231312441 in words is "two hundred forty trillion, five hundred fifty-four billion, two hundred thirty-one million, three hundred twelve thousand, four hundred forty-one".