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241005134232433 is a prime number
BaseRepresentation
bin110110110011000101100001…
…011010100011101101110001
31011121022212101011221112012201
4312303011201122203231301
5223042112003330414213
62212324121420423201
7101523021616364134
oct6663054132435561
91147285334845181
10241005134232433
116a87878131310a
12230444ab9a7b01
13a4628c071bb1c
1443729d438a21b
151cce16b1416dd
hexdb31616a3b71

241005134232433 has 2 divisors, whose sum is σ = 241005134232434. Its totient is φ = 241005134232432.

The previous prime is 241005134232389. The next prime is 241005134232437. The reversal of 241005134232433 is 334232431500142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200375830443889 + 40629303788544 = 14155417^2 + 6374112^2 .

It is a cyclic number.

It is not a de Polignac number, because 241005134232433 - 29 = 241005134231921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 241005134232392 and 241005134232401.

It is not a weakly prime, because it can be changed into another prime (241005134232437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120502567116216 + 120502567116217.

It is an arithmetic number, because the mean of its divisors is an integer number (120502567116217).

Almost surely, 2241005134232433 is an apocalyptic number.

It is an amenable number.

241005134232433 is a deficient number, since it is larger than the sum of its proper divisors (1).

241005134232433 is an equidigital number, since it uses as much as digits as its factorization.

241005134232433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 37.

Adding to 241005134232433 its reverse (334232431500142), we get a palindrome (575237565732575).

The spelling of 241005134232433 in words is "two hundred forty-one trillion, five billion, one hundred thirty-four million, two hundred thirty-two thousand, four hundred thirty-three".