Base | Representation |
---|---|
bin | 110110110011011101101101… |
… | …110001101000101101000111 |
3 | 1011121102100102120121000010212 |
4 | 312303131231301220231013 |
5 | 223043023204010200201 |
6 | 2212344055225510035 |
7 | 101524631430644135 |
oct | 6663355561505507 |
9 | 1147370376530125 |
10 | 241031111412551 |
11 | 6a8887a17a7009 |
12 | 2304953b64231b |
13 | a4651a0532715 |
14 | 4373d7a420755 |
15 | 1cceb8b9d8abb |
hex | db376dc68b47 |
241031111412551 has 16 divisors (see below), whose sum is σ = 245330672447520. Its totient is φ = 236738712900480.
The previous prime is 241031111412527. The next prime is 241031111412587. The reversal of 241031111412551 is 155214111130142.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241031111412551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241031111412521) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1669800641 + ... + 1669944981.
It is an arithmetic number, because the mean of its divisors is an integer number (15333167027970).
Almost surely, 2241031111412551 is an apocalyptic number.
241031111412551 is a deficient number, since it is larger than the sum of its proper divisors (4299561034969).
241031111412551 is a wasteful number, since it uses less digits than its factorization.
241031111412551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168946.
The product of its (nonzero) digits is 4800, while the sum is 32.
Adding to 241031111412551 its reverse (155214111130142), we get a palindrome (396245222542693).
The spelling of 241031111412551 in words is "two hundred forty-one trillion, thirty-one billion, one hundred eleven million, four hundred twelve thousand, five hundred fifty-one".
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